Sunday, February 25, 2007
primary 5 maths
I don't wanna sound dumb, but i'm stumped...
Goodness how to be secondary school relief teacher?
Labels: maths
I don't wanna sound dumb, but i'm stumped...
Goodness how to be secondary school relief teacher?
Labels: maths
I don't want you to think of me as an eavesdropper so I'll just say that I'm listening to music instead of my neighbour's maid flirting with my other neighbour's driver.
I like it when people think of me as an intellectual so I will list a bunch of intellectual-sounding books here, even those I don't plan to read.
Since I can't list my porn collection here, I'll just leave it this way until I can force myself to watch non-pornographic stuff, which may or may not happen.
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so easy ... chicken feet!
lol piece of cake.
Get all the perimeters of the unshaded region, then area formula for triangles and add together.
Take both area caculate as squares and minus those area of the triangles, and viola..a.... ur shaded region lol..actually i forgot the formula for triangles.
Area of Squares=100+64=164 sq cm
Non-Shaded areas= 0.5*18*10+0.5*(10-8)*10+0.5*8*8=90+10+32=132
Area of shaded area=164-132=32 sq cm
TADAH~ ^_^ (Pssst, do i get paid for teaching?)
Ooookkkk.. i know i'm dumb. stop it already!
just to make you feel even more dumb!!! coming from an arts student!
Explain to the students the formula for finding area of triangle, half X base X height.
so with that information you can find all the unshaded area.
area of GAE = 1/2 X 18 X 10 = 90
area of ABC = 1/2 X 2 X 10 = 10
area of CDE = 1/2 X 8 X 8 = 32
total unshaded area = 90 + 10 + 32 = 132
total shaded area = (10 X 10) + (8 X 8) - 132 = 164 - 132 = 32
cheers
scott!